Abstract
This work is related to billiards and their applications in geometric optics. It is known that perfectly invisible bodies with mirror surface do not exist. It is, therefore, natural to search for bodies that are, in a sense, close to invisible. We introduce a visibility index of a body measuring the mean angle of deviation of incident light rays, and derive a lower estimate for this index. This estimate is a function of the body’s volume and of the minimal radius of a ball containing the body. This result is far from being final and opens a possibility for further research.
1. Introduction
The idea of invisibility has always been attractive for people. Stories on magic cap and cloak of invisibility form an essential part of folklore, myths and fairy tales. Methods of camouflaging establishments, troops and other objects of importance are of great interest to the military at all times; one of the most famous developments of the twentieth century in this area is the stealth technology aiming at making airplanes invisible to enemy radar.
In the last decades, intensive work has been carried out on developing technology of meta-materials possessing unusual properties (e.g. [1]), having in mind, in particular, creating something like a transparent meta-material cover with varying refractive index that makes invisible every object placed inside.
An important and interesting mathematical construction in the two-dimensional case is proposed in the paper by Leonhardt [2]. It describes how to make an object invisible by wrapping a lens (a transparent material with varying refractive index) around it.
There is an interesting question: to what extent can one create the effect of invisibility, if only mirror systems are allowed to be used? Mirrors are much easier and cheaper for fabrication than hypothetical meta-material structures, and even than traditional lenses with controlled refractive index. Some results in this direction have already been obtained. There exist and are described (connected) bodies invisible from one point [3,4] and (infinitely connected) bodies invisible from two points [5]. There exist (connected and even simply connected) bodies invisible in one direction (that is, from an infinitely distant point) [6], (finitely connected) bodies invisible in two directions [7], as well as (infinitely connected) bodies invisible in three [8] and (in the two-dimensional case) in n-directions, where the number of directions is arbitrary [9].
On the other hand, there are negative results revealing restricted possibilities of mirror systems as compared with more sophisticated technologies. In particular, non-existence of perfectly invisible bodies (that is those that are invisible in any direction or (equivalently) from any point outside the body) is proved in [7]. Further, a conjecture proposed in [3] states that the set of light rays that are invisible for any fixed body has measure zero. This conjecture is closely connected with the long-standing Ivrii’s conjecture [10] stating that the measure of the set of periodic billiard trajectories in a bounded domain has measure zero. If Ivrii’s conjecture is true then, most probably, true also is the conjecture on invisible light rays.
At the moment Ivrii’s conjecture has been proved only for trajectories with three [11,12] and four [13,14] reflections. The corresponding invisibility conjecture for the case of three reflections is easily obtained by slightly rephrasing the proof of Ivrii’s conjecture with three reflections. A unified approach developed by Glutsyuk in [13] based on complexification of billiards allows one to derive both Ivrii’s and invisibility conjectures in the case of four reflections from his theorem of classification of four-reflective complex planar analytic billiards (Theorem 1.7 in [13]). Note that the proof of the conjectures in the case of four reflections is much more difficult than the case of three reflections.
In real life, quite common is the situation when perfect invisibility is impossible to achieve. In such cases, one tries to reach the effect of partial invisibility, or camouflaging, when the object, though not disappearing completely, still becomes difficult to detect by an observer. It is natural to set such a question in the framework of mirror invisibility. In order to state a mathematical problem, one needs first to determine an index of visibility, a certain positive quantity which is close to zero if the body is, in a sense, difficult to detect. This quantity should never vanish, since perfectly invisible bodies do not exist.
Then one should consider the question, how small can this index be made in a certain class of bodies? For example, if even the index does not vanish, is it possible to construct a sequence of bodies of constant volume with the index going to zero?
Choosing the visibility index is not an easy task; it is more difficult than just defining the notion of invisibility. The body is observed against a certain background, and the choice will depend, in particular, on the distance of the body from the background. In the limit, when the background is infinitely distant, the visibility index is determined by the angles of deviation of light rays from their original directions and does not depend on transverse displacement of the rays. This limit will be used later on in this paper.
The aim of the paper is to give (partial) answers to the questions stated above. If the body has volume A and is contained in a sphere of radius r, then its visibility index is not less than a certain positive value, a function of A and r. This function goes to zero when A is constant as .
2. Main definitions and statement of the results
First of all fix the notation. A body with specular surface is a bounded finitely connected domain with piecewise smooth boundary in Euclidean space with d≥2. It will be called a domain and designated by D. Since everything is about specular reflections in the framework of geometric optics, we adopt the notation of billiard theory and consider the billiard in .
Fix a domain D and take a sphere of radius R>0 centred at the origin and containing D. It is assumed that the background lies on the sphere. As a result of observation of the background one must conclude whether the body is or is not present here. For a point ξ on the sphere and a unit vector v such that 〈v,ξ〉<0 consider the trajectory of a billiard particle starting at ξ with the velocity v and the half-line with the endpoint ξ and the directing vector v, and denote by θ=θR,D(v,ξ) the angular distance between the (second) points of intersection of the trajectory and of the half-line with the sphere (figure 1).
Figure 1. The domain D is shown shaded (it has two connected components); θR(v,ξ) indicates the angular deviation of the particle reflected from D with respect to freely moving particle. (Online version in colour.)
We define the measure spaces
Take a monotone increasing function such that f(0)=0 and consider the value
Note that the equality does not yet guarantee invisibility of D. In fact, the domain D is invisible, if and only if for any R sufficiently large.
In the limit the quantity θ does not depend on the transverse displacement (shift) of the trajectory going away, but only on the angle between the initial and final velocities. Let us introduce some more notation. For the billiard trajectory entering the sphere at a point ξ and having a velocity v at this point, we denote by
Then in the limit mentioned above, θ is the angle between v and v+, , and one comes to the following formula for the visibility index, :
Denote by sd−1=|Sd−1|=2πd/2/Γ(d/2) the area of the (d−1)-dimensional unit sphere, and by bd=2πd/2/dΓ(d/2) the volume of the d-dimensional ball. One has, in particular, s0=2, s1=2π, s2=4π, b1=2, b2=π, b3=4π/3.
Assume that
Theorem 2.1 establishes a connection between the visibility index of a domain, its volume and the radius of a ball containing this domain.
Let a domainbe contained in a ball of radius r. Then its visibility index, its volume |D| and r are related by the inequality
Theorem 2.1
Note that the values and |D|/rd are preserved under a scaling transformation (applied to both D and the ambient ball). It is natural therefore that theorem 2.1 relates these two values.
It follows from theorem 2.1 that
Remark 2.2
One may wish to have a more direct estimate of the visibility index (without the term o(1)). We shall derive such estimates in the two- and three-dimensional cases for a particular choice of the function f. Namely, take ; the resulting visibility index
Note that the mean resistance of a convex domain can easily be determined; denoting by |∂C| the (d−1)-dimensional area of its boundary, one has . In the two- and three-dimensional cases one has, respectively, and . In particular, the mean resistances of the two- and three-dimensional balls, and , of radius r are equal, respectively, to and (see §§6.1.1 and 6.2 of [3] for details).
The following formulae for the mean resistance in the two- and three-dimensional cases are obtained from theorem 2.1 by direct substitution c=1/2, k=2,
The following theorem allows one to get rid of the term o(1) in the above formulae.
(a) Let a planar domain D with the area |D| be contained in a circle of radius r. Then
Theorem 2.3
It is instructive to rewrite these formulae in terms of reduced volume κD and reduced resistance defined by
It is interesting to note that
On the contrary, only rough estimates are known for the infimum of . In particular, the following estimates in the two- and three-dimensional cases follow directly from theorem 2.3,
These estimates are far from being sharp. Indeed, from the same Theorem 6.2 in [3] one can derive the exact value of the lower limit of when κD→1; in particular,
There is a question on a natural generalization of formula (2.4). Consider the relative volume of a domain in its convex envelope, and let the normalized resistance be chosen so that the resistance of the convex envelope of the body equals 1. Is it possible to derive a sensible estimate for the normalized resistance in the spirit of formula (2.4)?
The statement of theorem 2.3 can also be interpreted in terms of Newton’s problem of minimal resistance [15]. Consider a body moving in a rarefied medium of point particles. The medium is so rare that mutual interaction of particles is neglected, and particles are reflected elastically when hitting the body’s boundary. One needs to find a body, from a prescribed class of bodies, that has the smallest aerodynamic resistance. There has been a significant progress in this problem in 1990s and 2000s (e.g. [3,16–19]). Suppose now that the body D translates in the medium and at the same time rotates (somersaults) very slowly and chaotically. In this case, one is interested in minimizing the mean value of its resistance in all possible directions, i.e. the value . Theorem 2.3 gives a lower estimate of this value in a class of bodies with fixed volume.Remark 2.4
The statements of theorems 2.1 and 2.3 hold for broader classes of dynamical systems than billiards. It suffices that the system satisfies the following conditions:
(i) the motion is free outside a sphere of radius r; (ii) all the trajectories of the system are continuous curves; (iii) the standard measure dv dx is invariant under the dynamics of the system.Remark 2.5
In this case, the proofs (given in the next section) go through without change.
One can, for example, take the free dynamics outside with a pseudo-billiard law of reflection off the boundary ∂D; this law is induced by any one-to-one mapping of the segment [−π/2, π/2] onto itself preserving the measure .
Taking account of Jung’s inequality between the diameter diam(D) of a set D and the smallest radius r=r(D) of a ball containing D,
Remark 2.6
Further, using Jung’s inequality and the obvious relation diam(D)≤2r, the inequality in theorem 2.1 can be replaced with
3. Proofs of the theorems
All statements below are true up to subsets of measure zero.
Let us first prove theorem 2.1. We consider the billiard inside the ball of radius r and outside D. A particle starts moving at a point and with a velocity v∈Sd−1 directed inside the sphere Sd−1, then makes several reflections off D, and finally intersects Sd−1 again (at the point ξ+ and with the velocity v+) and disappears at the moment of intersection. The phase space of the billiard is , and its volume V (with respect to the standard Liouville measure dv dx) equals
Denote by lD,r(v,ξ) the length of the billiard trajectory with the initial data until the final intersection with . We use Santaló–Stoyanov formula (e.g. [21,22]), which in our case states that the phase volume is greater than or equal to the integral of the length of billiard trajectories over the initial data,
Further, take an orthonormal coordinate system, x=(x1,…xd), centred at the origin and denote by the rotation of about the origin such that
(a) under this rotation, v goes to ; that is, ;
(b) the two-dimensional subspace of spanned by the vectors v and is invariant under ;
(c) acts as identity on the orthogonal complement to this subspace.
Denote the upper and lower hemispheres of radius r by
It follows (by Cavalieri’s principle) that the bijective mapping between the space with the measure μ (recall that it is defined by dμ(v,ξ)=|〈v, n(ξ)〉| dv dξ) and the space with the measure defined by dv dη′ is also measure preserving. This implies, in particular, that
Now define the measures μ± on by dμ±=sd−1 dη′; then the mappings defined by
We have
Fix a value 0<ϕ<π and let Σϕ be the set of values such that the angle between v and v+=v+D(v,ξ) is greater or equal than ϕ, that is,
From (3.2) and (3.3), taking into account that , we get
(a) Denote for brevity and recall that f(ϕ) is positive and monotone increasing for 0<ϕ<π. By Chebyshev’s inequality for t>0 one has
If then the angle between v and v+ is less than ϕ, and denoting by α=α(v) and α+=α(v+) the angles formed by the vectors v and v+ with , 0≤α, α+≤π; we have |α−α+|≤ϕ.
(b) In the case d=2, one obviously has
Consider the three-dimensional subspace of spanned by the vectors v, v+ and . The restrictions of and on this subspace are rotations by the angles α and α+, respectively. Let w and w+ be unit vectors in this subspace pointing at directions of the rotation axes. Both w and w+ are orthogonal to . The restriction of on this subspace acts as a rotation by an angle β, and its restriction on the orthogonal complement to this subspace is an identity. We have
Introduce an orthonormal coordinate system x, y, z in the chosen subspace, where the third coordinate axis coincides with the dth axis of the original space and the origin coincides with the origin in the space . In this system, the coordinate vectors v, v+ and take the form
One has
In what follows, we shall use the same notation and for the restrictions of the corresponding rotations on our three-dimensional subspace. It is convenient to represent them in the quaternionic form: is the action u↦quq−1 of the quaternion
Thus, we have
We now need to estimate the integral in the right-hand side of this inequality. Integrating by ξ gives us the factor bd−1rd−1. Integrating by v over Sd−1 amounts to integration with the differential over the interval α∈[0,π]. Thus, we get
Introducing the functions by
(c) Now consider the first term in the right-hand side of (3.5).
Recall that the mapping is defined by T(v,ξ)=(v+D(v,ξ),ξ+D,R(v,ξ)). It preserves the measure μ, and therefore induces a measure on concentrated on the graph of T and whose projections on and coincide with μ. The push forward of this measure under the map3 (let it be denoted by νD,r) is a measure on whose projections on and on coincide, respectively, with μ− and μ+.
Therefore, we have
4That is, we have
(d) From (3.1), (3.5), (3.6), (3.11) and (3.13), we obtain
Using asymptotic formulae (2.2) and (3.12) for f and , respectively, and replacing both terms in the right-hand side of (3.14) with their approximated values (as ϕ→0+), we obtain the expression
Let us now prove theorem 2.3. Here we have and use the notation in place of in this particular case.
If d=2, substitute s1=2π, b1=2, s0=2 and into (3.14) to obtain
Our goal is to prove the inequality
Consider two cases. If , the infimum in (3.17) is attained at , and substituting z* in (3.17), we get (3.18). On the other hand, if , we obviously have (since D is contained in a circle of radius r)
If d=3, one has s2=4π, b2=π, s1=2π and , and inequality (3.14) takes the form
We are going to prove the inequality
After a simple algebra one concludes that if , we have h′(z)<0 for all z>0, has a unique zero z=3/4. If , the equation h′(z)=0 has two positive zeros (coinciding when ). The smallest zero (which is a local minimizer of h if is strictly smaller than 27/256) satisfies the inequality 0<z*≤3/4. It is also straightforward to check that
Consider two cases. If , we substitute z=z* in (3.19) and use (3.21) to obtain . Taking the third power of both sides of this inequality and using that (1−2z/3)3<1−z for 0<z≤3/4, we come to (3.20). If, otherwise, , we use that , and therefore . It follows that , and (3.20) again follows. Thus, statement (b) of theorem 2.3 is also proved.
Data accessibility
This work does not have any experimental data.
Competing interests
I declare I have no competing interests.
Funding
This work was supported by Portuguese funds through CIDMA—Center for Research and Development in Mathematics and Applications and FCT—Portuguese Foundation for Science and Technology, within the project UID/MAT/04106/2013.
Acknowledgements
I am grateful to V. Protasov for a useful discussion and to the anonymous referees for suggestions that helped to improve the quality of the text.
Footnotes
1 In this case, the diameter of the domains should go to infinity.
2 Of course, it does not depend on the radius r of the ambient sphere and does not change when the domain is displaced within the sphere; see Proposition 1.1 of ch. 1 in [3].
4 This value is really attained at the (optimal) measure supported on the subspace . This measure induces the mass transport in the vertical direction sending each point of the lower hemisphere to the point of the upper hemisphere with the same abscissa.
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